Видео ютуба по тегу Y^2=4Ax

Let P(4, 4V3) be a point on the parabola y2 = 4ax and PQ be a focal chord ofthe parabola. If M and
Let P(4, 4V3) be a point on the parabola y2 = 4ax and PQ be a focal chord ofthe parabola. If M and
Consider Point (at^2 2at) on y^2 = 4ax | JEE Advanced 2026 | Full Concept Advanced Practice Problems
Consider Point (at^2 2at) on y^2 = 4ax | JEE Advanced 2026 | Full Concept Advanced Practice Problems
Q) If the area of the region bounded by the curve 𝐲^𝟐=𝟒𝐚𝐱 and the line x = 4a is 𝟐𝟓𝟔/𝟑 ,
Q) If the area of the region bounded by the curve 𝐲^𝟐=𝟒𝐚𝐱 and the line x = 4a is 𝟐𝟓𝟔/𝟑 ,
Q) Using integration, find the area of the region bounded by the parabola 𝐲^𝟐=𝟒𝐚𝐱 and
Q) Using integration, find the area of the region bounded by the parabola 𝐲^𝟐=𝟒𝐚𝐱 and
Q) If the area of the region bounded by the curve 𝐲^𝟐=𝟒𝐚𝐱 and the line x = 4a is 𝟐𝟓𝟔/𝟑 , value of a
Q) If the area of the region bounded by the curve 𝐲^𝟐=𝟒𝐚𝐱 and the line x = 4a is 𝟐𝟓𝟔/𝟑 , value of a
Q) Using integration, find the area of the region bounded by the parabola 𝐲^𝟐=𝟒𝐚𝐱 and
Q) Using integration, find the area of the region bounded by the parabola 𝐲^𝟐=𝟒𝐚𝐱 and
Парабола № 1, гл. 10. Введение, уравнение параболы: y^2 = 4ax.
Парабола № 1, гл. 10. Введение, уравнение параболы: y^2 = 4ax.
The angle of intersection of the parabolas y² = 4ax and x² = 4ay at the origin is(a) π/6(b) π/3(c) π
The angle of intersection of the parabolas y² = 4ax and x² = 4ay at the origin is(a) π/6(b) π/3(c) π
G2_Find orthogonal trajectory of y^2=4ax #maths #studywithme #education #channel #shortvideo
G2_Find orthogonal trajectory of y^2=4ax #maths #studywithme #education #channel #shortvideo
A point P in the first quadrant, lies on y2 = 4ax , and keeps a distance of 5a unit from the foc
A point P in the first quadrant, lies on y2 = 4ax , and keeps a distance of 5a unit from the foc
P-5:Semi-latus rectum of the parabola y^2=4ax,is the harmonic mean b/w segments of any focal chord
P-5:Semi-latus rectum of the parabola y^2=4ax,is the harmonic mean b/w segments of any focal chord
Prove that area of triangle inscribed in the parabola y2 = 4ax is 1/8a(y1 - y2)(y2 - y3)(y3 - y1)
Prove that area of triangle inscribed in the parabola y2 = 4ax is 1/8a(y1 - y2)(y2 - y3)(y3 - y1)
TP and TQ are tangents to the parabola y^2=4ax and the normals at P and Q meet at a point R on
TP and TQ are tangents to the parabola y^2=4ax and the normals at P and Q meet at a point R on
The vertex A of the parabola y^2=4ax is joined to any point P on it and PQ is drawn at right angles
The vertex A of the parabola y^2=4ax is joined to any point P on it and PQ is drawn at right angles
Let the tangent to the parabola y^2=4ax meets the axis in T and the tangent at the vertex A in Y.
Let the tangent to the parabola y^2=4ax meets the axis in T and the tangent at the vertex A in Y.
If a chord which is normal to the parabola y^2=4ax at one end subs tend a right angle at vertex,
If a chord which is normal to the parabola y^2=4ax at one end subs tend a right angle at vertex,
If the Normal to the parabola y^2=4ax at t1 meets the parabola again at point t2,then t2 =-t1-2/t1
If the Normal to the parabola y^2=4ax at t1 meets the parabola again at point t2,then t2 =-t1-2/t1
Normal to the parabola y^2=4ax ​ @mathsclass9033
Normal to the parabola y^2=4ax ​ @mathsclass9033
Tangents to a parabola y^2 =4ax @mathsclass9033
Tangents to a parabola y^2 =4ax @mathsclass9033
Length of focal chord of parabola y^2=4ax @mathsclass9033
Length of focal chord of parabola y^2=4ax @mathsclass9033
A circle and a parabola y^2=4ax intersect in four points show that the algebraic sum of the ordinate
A circle and a parabola y^2=4ax intersect in four points show that the algebraic sum of the ordinate
परवलय y^2 = 4ax और उसके नाभि लम्ब से घिरे क्षेत्र का क्षेत्रफल ज्ञात कीजिए।
परवलय y^2 = 4ax और उसके नाभि लम्ब से घिरे क्षेत्र का क्षेत्रफल ज्ञात कीजिए।
Area between y2=4ax and x2= 4ay
Area between y2=4ax and x2= 4ay
If the area of the region bounded by the curve y2 = 4ax and the line x = 4a is 256/3 sq. units,
If the area of the region bounded by the curve y2 = 4ax and the line x = 4a is 256/3 sq. units,
Show that the tangent with slope m to y^2 = 4ax is the line y= mx + a/m.
Show that the tangent with slope m to y^2 = 4ax is the line y= mx + a/m.